SOLUTION: find the equation of the tangent line:
1)
f(x)=√(25-x^2) at the point where x=4
2)
f(x)=x^2+√x at the point where x=1
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-> SOLUTION: find the equation of the tangent line:
1)
f(x)=√(25-x^2) at the point where x=4
2)
f(x)=x^2+√x at the point where x=1
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Question 1107335: find the equation of the tangent line:
1)
f(x)=√(25-x^2) at the point where x=4
2)
f(x)=x^2+√x at the point where x=1 Answer by KMST(5328) (Show Source):
As a calculus problem:
The derivative of
For ,
is the slope of the tangent.
Otherwise, is the half of the circle with equation <-->
The tangent at the point with
is perpendicular to the radius at that point.
The equation of the line containing that radius is .
The slope of a line perpendicular to that radius is
Either way, the equation of the tangent
at the point with , with slope is
2) is defined for .
The slope of the tangent at is
The equation of the tangent line
passing through the point with ,
with slope is