SOLUTION: Three consecutive odd integers are such that their sum is more than 57 decreased by twice the greatest of the three integers. What is the smallest integer?

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Question 1107187: Three consecutive odd integers are such that their sum is more than 57 decreased by twice the greatest of the three integers. What is the smallest integer?
Found 2 solutions by stanbon, TeachMath:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Three consecutive odd integers are such that their sum is more than 57 decreased by twice the greatest of the three integers. What is the smallest integer?
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1st:: 2x-1
2nd:: 2x+1
3rd:: 2x+3
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Equation::
6x+3 > 57-2(2x+3)
6x+3 > 57-4x-6
10x > 48
x > 4.8
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x = 5
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Answer:: 2x+3 = 2*5+3 = 13
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Cheers,
Stan H.
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Answer by TeachMath(96) About Me  (Show Source):
You can put this solution on YOUR website!
smallest odd integer: 9

With the smallest odd integer being S, finish solving the following inequality:
S + S + 2 + S + 4 > 57 - 2(S + 4)
3S + 6 > 57 - 2S - 8
3S > 43 - 2S