SOLUTION: Need help with this problem please. Find the equation of the line that contains the point (-2,-1) and has slope -1/2. I tried to work the problem but haven't gotten the corre

Algebra ->  Linear-equations -> SOLUTION: Need help with this problem please. Find the equation of the line that contains the point (-2,-1) and has slope -1/2. I tried to work the problem but haven't gotten the corre      Log On


   



Question 110718: Need help with this problem please.
Find the equation of the line that contains the point (-2,-1) and has slope -1/2.
I tried to work the problem but haven't gotten the correct answer.
m=-1/2
(y1,x1)= (-2,-1)
y-y1=m(x-x1)
y-(-1)=-1/2(x-(-2))
y-(-1)=-1/2x+(-3)
y=-1/2x+2

Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
Need help with this problem please.
Find the equation of the line that contains the point (-2,-1) and has slope -1/2.
:
You seem to have the right idea, however, I's going to give you the whole procedure and you can decide where you went wrong.
:
We're going to use the point/slope form: y - y1 = m(x - x1)
;
In your problem x1 = -2; y1 = -1; m = -1/2
:
So we have:
y - (-1) = -1%2F2(x - (-2))
:
Remember minus a minus is a plus:
y + 1 = -1%2F2(x + 2)
:
Multiply what's inside the bracket by -1/2
y + 1 = -1%2F2x - 1
:
Subtract 1 from both sides:
y = -1%2F2x - 1 - 1
:
y = -1%2F2x - 2