SOLUTION: A rocket is fired upward from some initial distance above the ground. Its height in​ feet, h,above the​ ground, t seconds after it is​ fired, is given by h=-16

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: A rocket is fired upward from some initial distance above the ground. Its height in​ feet, h,above the​ ground, t seconds after it is​ fired, is given by h=-16      Log On


   



Question 1107103:
A rocket is fired upward from some initial distance above the ground. Its height in​ feet, h,above the​ ground, t seconds after it is​ fired, is given by h=-16t^2+48+4320.
What is the​ rocket's maximum​ height?
How long does it take for the rocket to reach its maximum​ height?
After it is​ fired, the rocket reaches the ground at t= sec.

Found 2 solutions by Alan3354, ikleyn:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
A rocket is fired upward from some initial distance above the ground. Its height in​ feet, h,above the​ ground, t seconds after it is​ fired, is given by h=-16t^2+48+4320.
=============
How long does it take for the rocket to reach its maximum height?
h=-16t^2+48+4320
h=-16t^2 + 4368
The Max is the vertex of the parabola, at t = -b/2a
b = 0 --? Max = 4368 feet.
======================
After it is​ fired, the rocket reaches the ground at t= sec.
I'll take your word on that.

Answer by ikleyn(52855) About Me  (Show Source):
You can put this solution on YOUR website!
.

A rocket is fired upward from some initial distance above the ground. Its height in​ feet, h,above the​ ground,
t seconds after it is​ fired, is given by h=-16t^2+48+4320.
What is the​ rocket's maximum​ height?
How long does it take for the rocket to reach its maximum​ height?
After it is​ fired, the rocket reaches the ground at t= sec.
~~~~~~~~~~~~~~~~~~~~~~~~

In the post,  you  INCORRECTLY  presented the height function.

The correct formula is   h(t) = -16t^2 + 48t + 4320.

So,  double check with your sources.

In this formula,  the coefficient at  "t"  is the initial velocity  (the positive direction is vertically up);
the constant term is the initial height of the launch.

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To see many similar solved problems of this type and to learn on how to solve them,  look into the lessons
    - Problem on a projectile moving vertically up and down
    - Problem on an arrow shot vertically upward
    - Problem on a ball thrown vertically up from the top of a tower
    - Problem on a toy rocket launched vertically up from a tall platform

Also,  you have this free of charge online textbook in ALGEBRA-I in this site
    - ALGEBRA-I - YOUR ONLINE TEXTBOOK.

The referred lessons are the part of this textbook under the topic "Projectiles launched/thrown and moving vertically up and dawn".


Save the link to this online textbook together with its description

Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson

to your archive and use it when it is needed.


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