SOLUTION: Find the sum x+y, where x and y are positive integers and {{{ x^2(x-y)=3703 }}}.

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Question 1107094: Find the sum x+y, where x and y are positive integers and +x%5E2%28x-y%29=3703+.
Found 2 solutions by ankor@dixie-net.com, TeachMath:
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
Find the sum x+y, where x and y are positive integers and x%5E2+%2A+%28x-y%29=3703.
x%5E3-x%5E2y+=+3703
rearrange to
x%5E2y+=+x%5E3+-+3703
y = %28x%5E3-3703%29%2Fx%5E2
y = %28x-%283703%2Fx%5E2%29%29
Only positive integer solution (used the table on my Ti83)
x = 23
y = 16
(x+y) = 39
:
;
Check
23^2 * (23-16) =
529 * 7 = 3703

Answer by TeachMath(96) About Me  (Show Source):
You can put this solution on YOUR website!

x^2 (x - y) = 3703
x^2 (x - y) = 23^2(7)
So, x^2 = 23^2, and x = 23

x - y = 7
23 - y = 7
23 - 7 = y
16 = y

x + y = 23 + 16 = 39