SOLUTION: Find the remaining trigonometric ratios. cos(x) = &#8722; 1/5, &#960; < x < 3&#960;/2

Algebra ->  Trigonometry-basics -> SOLUTION: Find the remaining trigonometric ratios. cos(x) = &#8722; 1/5, &#960; < x < 3&#960;/2       Log On


   

Question 1106998: Find the remaining trigonometric ratios.
cos(x) = − 1/5, π < x < 3π/2
Answer by ikleyn(52833) About Me  (Show Source):
You can put this solution on YOUR website!
.
sin(x) = -sqrt%281-cos%5E2%28x%29%29 = -sqrt%281-%28-1%2F5%29%5E2%29 = -sqrt%281+-+1%2F25%29 = -sqrt%2824%2F25%29 = -sqrt%2824%29%2F5 = -%282%2Asqrt%286%29%29%2F5.


The sign is "minus" ("-") at the square root, since the angle is in QIII.


Regarding other trigonometric functions, simply recall their definitions.