SOLUTION: In Timothy's money box there are 71 coins. Some are 5 cent coins and the rest are 10 cent coins. Their total value is $5.60, find the number of each type
Algebra ->
Customizable Word Problem Solvers
-> Coins
-> SOLUTION: In Timothy's money box there are 71 coins. Some are 5 cent coins and the rest are 10 cent coins. Their total value is $5.60, find the number of each type
Log On
Question 1106988: In Timothy's money box there are 71 coins. Some are 5 cent coins and the rest are 10 cent coins. Their total value is $5.60, find the number of each type Answer by josmiceli(19441) (Show Source):
You can put this solution on YOUR website! Let = the number of 5 cent coins
Let = the numbe of 10 cent coins
--------------------------------------
(1)
(2) ( in cents )
-------------------------------------
Multiply both sides of (1) by and
subtract (1) from (2)
(2)
(1)
--------------------------
and
(1)
(1)
--------------------------
The number of 5 cent coins is 30
The number of 10 cent coins is 41
