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That's the wrong answer.
If you mean this:
a-4b(a+b)
then we distribute only the -4b:
a-4ba-4bČ
and since "a" comes before "b" in the alphabet
we write "ba" as "ab" to keep alphabetical order:
a-4ab-4bČ <--final answer
---------------------------
However if you meant this
(a-4b)(a+b)
then we must first write the second parenthese
beside each of the two terms in the first
parentheses like this:
a(a+b)-4b(a+b)
Then we distribute twice, once with the "a"
over (a+b), and then again with the -4b over
the (a+b)
aČ+ab-4ba-4bČ
Now since "ba" is the same as "ab" we write
aČ+ab-4ab-4bČ
Finally since +ab and -4ab are like terms,
we combine the coefficients and get
aČ-3ab-4bČ <--final answer
Edwin