Question 1106784: A basket contains 18
eggs, 4
of which are cracked. If we randomly select 8
of the eggs for hard boiling, what is the probability of the following events?
a. All of the cracked eggs are selected.
b. None of the cracked eggs are selected.
c. Two of the cracked eggs are selected.
Answer by Boreal(15235)   (Show Source):
You can put this solution on YOUR website! All are cracked
one way is 4/18*3/17*2/16*1/15*1*1*1*1=0.0003,
But, the numerator may be ordered in different ways, 8C4, which is 70. The product is 0.0270
None cracked is way of choosing 8 from 14, or 3003. The probability is 3003/43758=0.0686
Two of the cracked eggs are selected, 4C2*14C6/18C8, the numerator the ways to choose 2 from 4 cracked and 6 from 14.
This is 0.4118.
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