Question 110677This question is from textbook College Algebra
: I am not sure if this is the right topic I chose could not find one for Inverse Variation:
According to Newton's Law of Graviation, the force of attractions between two objects varies jointly as thir masses and inversely as the square of the distance between them. How does the force change if each of their masses is tripled but the distance bewteen them is cut to one-third?
This question is from textbook College Algebra
Found 2 solutions by stanbon, MathLover1:
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! According to Newton's Law of Graviation, the force of attractions between two objects varies jointly as thir masses and inversely as the square of the distance between them.
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Basic Formula:
F = km1m2/d^2
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How does the force change if each of their masses is tripled but the distance bewteen them is cut to one-third?
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After modify masses and force:
F = k (3m1)(3m2)/[(1/3)d]^2
F = k 9m1m2/[d^2/9]
F = (81)[km1m2/d^2]
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Answer: The force is multiplied by 81.
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Cheers,
Stan H.
Answer by MathLover1(20850)  (Show Source):
You can put this solution on YOUR website! According to the definition of inverse variation, we can say that "as one quantity increases, the other quantity decreases".
example: "You got a job stuffing envelopes. So, the more time you work, the less envelope you have left to stuff".
Newton's Force of Gravity Equation (The Universal Gravity Equation is:
 involves both direct and inverse variation. Mathematically, G is the constant of variation or the universal gravitational constant.
1.  and product of  vary  . If the mass product increases, then the force between the centers of the two masses also increases by the same factor, and vice versa, (when the distance is unchanged.)
you need this part:
2. and  vary  .
If the  , the  of gravity between two objects  , and if the  , (when the masses are unchanged.)
So, if each of their masses is tripled but the  , then the will be  times greater.
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