SOLUTION: A football stadium has a capacity of 53,983. If 47,892 fans attended the game, what percent of the seats were empty?

Algebra ->  Percentage-and-ratio-word-problems -> SOLUTION: A football stadium has a capacity of 53,983. If 47,892 fans attended the game, what percent of the seats were empty?      Log On


   

Question 1106497: A football stadium has a capacity of 53,983. If 47,892 fans attended the game, what percent of the seats were empty?
Answer by ikleyn(52903) About Me  (Show Source):
You can put this solution on YOUR website!
.
%28%2853983-47892%29%2F53983%29%2A100 = 11.28%  (approximately).


The steps are:

    1.  Take the difference.

    2.  Divide the difference by the base value to get the fraction.

    3.  Multiply the fraction by 100 to convert it to percentage value.

------------
On percentage problems see the lessons
    - Percentage problems
    - Percentage word problems (Type 1 problems, Finding the Part)
    - Percentage word problems (Type 2 problems, Finding the Rate)
    - Percentage word problems (Type 3 problems, Finding the Base)
    - More complicated percentage problems
    - Problems on percentage that lead to unexpected results
in this site.