Question 1106481: Find two consecutive odd integers such that their product is 119 more than 7 times their sum.
Answer by Boreal(15235)   (Show Source):
You can put this solution on YOUR website! x and x+2 are the integers
x(x+2)=7(x+x+2)+119
x^2+2x=7(2x+2)+119=14x+133
x^2-12x-133=0
(x-19)(x+7)=0
x=19, x+2=21
(19 and 21) sum is 40 product is 399, which is 119 more than 280. ANSWER
also
x=-7, x+2=-5
(-7 and -5), sum is -12 and product is 35. That is 119 more than -84, 7 times their sum. ANSWER
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