SOLUTION: Bag a contains 9 red marbles and 3 green marbles. Bag b contains 9 black marbles and 6 orange marbles. Find the probability of selecting one green marble from bag a and one black m
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-> SOLUTION: Bag a contains 9 red marbles and 3 green marbles. Bag b contains 9 black marbles and 6 orange marbles. Find the probability of selecting one green marble from bag a and one black m
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Question 1106432: Bag a contains 9 red marbles and 3 green marbles. Bag b contains 9 black marbles and 6 orange marbles. Find the probability of selecting one green marble from bag a and one black marble from bag b Answer by math_helper(2461) (Show Source):
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For bag 'a' there is a probability of 3/12 of selecting green (3 greens and 9 reds add to 12 total).
For bag 'b' there is a probability of 9/15 of selecting black.
Because the two events are independent, the probability of the first event AND second event is the product of the two events individually:
(3/12)(9/15) = (1/4)(3/5) = 3/20
