SOLUTION: A 32 year old women realized that her age is twice the sum of her two children’s ages. Her son Jose is two years older than her daughter Sophia. How old are Sophia and Jose.

Algebra ->  Customizable Word Problem Solvers  -> Age -> SOLUTION: A 32 year old women realized that her age is twice the sum of her two children’s ages. Her son Jose is two years older than her daughter Sophia. How old are Sophia and Jose.      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 1106354: A 32 year old women realized that her age is twice the sum of her two children’s ages. Her son Jose is two years older than her daughter Sophia. How old are Sophia and Jose.
Answer by ikleyn(52787) About Me  (Show Source):
You can put this solution on YOUR website!
.
From the condition, you havr these 2 equations

J + S = 16,    (1)     ("Her age is twice the sum of her two children ages";  16 = 32%2F2)
J - S  = 2     (2)     ("Her son Jose is two years older than her daughter Sophia.")


Add equations (1) and (2). You will get

2J = 16+2 = 18  ====>  J = 18%2F2 = 9.


Answer.  Jose is 9 years old.  Sofia is 9-2 = 7 years old.