Question 1106201: A cassette shop charges Rupees 15 for renting a video cassette for the first day. It charges rupees 2 extra for every additional day. What will be the algebraic expression for the amount that Sara would pay. If she rents a video cassette for n days
Found 2 solutions by josgarithmetic, ikleyn:
Answer by josgarithmetic(39630)   (Show Source):
Answer by ikleyn(52893)  (Show Source):
You can put this solution on YOUR website! .
I read and understand the condition differently:
In the first day the shop charges 15 rupees, in the 2-nd day it charges 15+2 = 17 rupees,
in the third day it charges 17+2 = 19 rupees . . . and so on.
What is a bill after "n" days ?
So, it is about finding the sum of the arithmetic progression
15, 17, 19, . . . 15+2(n-1).
The first term is 15, the common difference is 2, and the number of terms = number of days = n.
The answer is: the balance, i.e. the sum of n terms, is  =  =  =  = (14+n)*n.
Solved.
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On arithmetic progressions, see the lessons in this site:
- Arithmetic progressions
- The proofs of the formulas for arithmetic progressions
- Problems on arithmetic progressions
- Word problems on arithmetic progressions
- Mathematical induction and arithmetic progressions
- One characteristic property of arithmetic progressions
- Solved problems on arithmetic progressions
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- ALGEBRA-II - YOUR ONLINE TEXTBOOK.
The referred lessons are the part of this online textbook under the topic "Arithmetic progressions".
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Free of charge online textbook in ALGEBRA-II
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