SOLUTION: The perimeter of a rectangle is 38ft. The length is 1ft longer than the width. Find the dimensions. Write a system of linear equations and solve the resulting system. Let X be the

Algebra ->  Linear-equations -> SOLUTION: The perimeter of a rectangle is 38ft. The length is 1ft longer than the width. Find the dimensions. Write a system of linear equations and solve the resulting system. Let X be the       Log On


   

Question 1106101: The perimeter of a rectangle is 38ft. The length is 1ft longer than the width. Find the dimensions. Write a system of linear equations and solve the resulting system. Let X be the length and y be the width.
Answer by josgarithmetic(39630) About Me  (Show Source):
You can put this solution on YOUR website!
w for width
w+1 for length
2w%2B2%28w%2B1%29=38


If following your description the way given, then
x, length
y, width

x=y%2B1
and
2x%2B2y=38