SOLUTION: A and B are acute angles. Cos A equals 24/25 and Tan B equals 15/8. Find the exact value of sin A-b. Show steps, please. I know I'm supposed to use the cos and tan to get sin fo

Algebra ->  Trigonometry-basics -> SOLUTION: A and B are acute angles. Cos A equals 24/25 and Tan B equals 15/8. Find the exact value of sin A-b. Show steps, please. I know I'm supposed to use the cos and tan to get sin fo      Log On


   

Question 1106069: A and B are acute angles. Cos A equals 24/25 and Tan B equals 15/8. Find the exact value of sin A-b.
Show steps, please. I know I'm supposed to use the cos and tan to get sin for the formula, and I got 9/5, but I have no idea what I'm supposed to do next or what to do with it.
Answer by greenestamps(13206) About Me  (Show Source):
You can put this solution on YOUR website!


sin%28A-B%29+=+sinAcosB-cosAsinB

You are given that cosA is 24/25 and tanB is 15/8. You can use those pieces of information to find the values of sinA, sinB, and cosB; then you will have all the pieces you need to evaluate sin(A-B).

cosA=24/25 means you have a right triangle with one leg 24 and hypotenuse 25; the Pythagorean Theorem tells you the other leg is 7. So now you can find the value of sinA.

tanB=15/8 tells you you have a right triangle with legs 15 and 8; the Pythagorean Theorem tells you the hypotenuse is 17. So now you can find the values of sinB and cosB.

Use your basic definitions of the basic trig functions to finish the problem....