SOLUTION: using the two equations below, solve for x and y using three different methods, substituion, addition and graphing. -2x+3y=6 3x-5y=-11

Algebra ->  Expressions-with-variables -> SOLUTION: using the two equations below, solve for x and y using three different methods, substituion, addition and graphing. -2x+3y=6 3x-5y=-11      Log On


   



Question 110604: using the two equations below, solve for x and y using three different methods, substituion, addition and graphing.
-2x+3y=6
3x-5y=-11

Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
using the two equations below, solve for x and y using three different methods, substitution, addition and graphing.
-2x + 3y = 6
3x - 5y =-11
:
Substitution:
Rearrange the 1st equation to be used for subsitution:
3y = 2x + 6
y = 2%2F3x + 6%2F3; divided equation by 3
y = 2%2F3x + 2
:
Substitute (2%2F3x + 2) for y in the 2nd equation:
3x - 5(2%2F3x + 2) = -11
:
3x - 10%2F3x - 10 = -11
;
9%2F3x - 10%2F3x = -11 + 10
:
-1%2F3x = -1
:
1%2F3x = 1; multiplied by -1 to get rid of the negatives
:
x = 3; Multiplied by 3 to get rid of the fraction
:
Find y using the y = 2%2F3x + 2
y = 2%2F33 + 2
y = 2 + 2
y = 4
:
Our solution x = 3; y = 4
:
Substitute for x and y in the 2nd equation to confirm our solutions:
3x - 5y =-11
:
3(3) - 5(4) =
9 - 20 = -11
:
:
Elimination:
-2x + 3y = 6
3x - 5y =-11
:
Multiply the 1st equation by 3 and the 2nd equation by 2:
-6x + 9y = 18
+6x -10y = -22
---------------adding eliminates x, find y:
0x - 1y = -4
y = +4
Find x just like we did before using substitution for y in either equation
:
To graph this:
y = 2%2F3x + 2; from above:
and
3x - 5y =-11
-5y = - 3x - 11
5y = 3x + 11; multiplied by -1 to get rid of all those negatives
y = 3%2F5x + 11%2F5
:
Plot these to equations, should look like this
+graph%28+500%2C+500%2C+-6%2C+8%2C+-2%2C+5%2C+%282%2F3%29x+%2B2%2C+.6x%2B%2811%2F5%29%29+
:
Not very clear but they should intersect at x=3, y=4
:
How about this? Did it explain these three methods to you?