You can put this solution on YOUR website! Find two consecutive odd integers such that twice the first is three more than the second
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1st:: 2x-1
2nd:: 2x+1
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Equations:
2(2x-1) = 2x+1 + 3
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4x-2 = 2x+4
2x = 6
x = 3
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1st:: 2x-1 = 5
2nd:: 2x+1 = 7
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Cheers,
Stan H.
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