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Question 1105910: A woman had two investments, one paying a 6% dividend. The other is $680 more than half the first investment and pays a 5% dividend. If the total return is $102, find the investments.
A man invested a total of $1200 into two accounts, one paying a 4% dividend, the other paying a 6% dividend. The total interest earned was $57. How much was invested into each account?
Answer by ikleyn(52787)   (Show Source):
You can put this solution on YOUR website! .
A man invested a total of $1200 into two accounts, one paying a 4% dividend, the other paying a 6% dividend.
The total interest earned was $57. How much was invested into each account?
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x + y = 1200, (1) ("A man invested a total of $1200 into two accounts")
0.04x + 0.06y = 57. (2) ("The total interest earned was $57")
Thus you have the system of 2 equations in 2 unknowns.
You can solve it using the substitution method.
For it, express y = 1200-x from the first equation and substitute it into the second equation. You will get
0.04x + 0.06*(1200-x) = 57,
0.04x + 72 - 0.06x = 57 ====> -0.02x = 57 - 72 = -15 ====> x =  = 750.
So, $750 was invested at 4% and the rest $1200 - $750 = $450 was invested at 6%.
Check. 0.04*750 + 0.06*450 = 57 dollars. ! Correct !
Answer. $750 was invested at 4% and $450 was invested at 6%.
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To see other similar solved problems on investment, look into the lesson
- Using systems of equations to solve problems on investment
in this site.
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