SOLUTION: A box contains with 15 red balls, 10 white balls, 20 blue balls and 5 yellow balls. Two balls were selected one after one with replacement. Calculate the probability for followin

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Question 1105631: A box contains with 15 red balls, 10 white balls, 20 blue balls and 5 yellow balls.
Two balls were selected one after one with replacement.
Calculate the probability for following incidents.
1) both the balls to be white
2) first ball to be red and second to be white
3) none of the balls to be yellow
4) either to be red or white or red and white
5) second ball NOT to be a blue ball
6) first ball to be a yellow
7) at least one ball to be a blue ball
8) more ever to be one red ball
9) first ball to be a white ball and second ball NOT to be a white ball
10) only one ball to be a red ball
Answer by rothauserc(4718) About Me  (Show Source):
You can put this solution on YOUR website!
There are 15 + 10 + 20 + 5 = 50 balls in the box
:
The balls are selected with replacement
:
1) (10/50) * (10/50) = 1/25
:
2) (15/50) * (10/50) = 3/50
:
3) (45/50) * (45/50) = 81/100
:
4) (15/50) + (10/50) + (3/50) = 28/50 = 14/25
:
5) 1 - (20/50) = 3/5
:
6) (5/50) = 1/10
:
7) (20/50) + (20/50) = 4/5
:
8) ?
:
9) (10/50) * (1 - (10/50)) = (1/5) * (4/5) = 4/25
:
10) (15/50) * (1 - (15/50)) = (3/10) * (7/10) = 21/100