Question 1105615: Red balls=15, White balls=10, Blue balls=20, Yellow balls=5
If a ball was randomly selected; what is the probability of a ball
1) TO BE yellow OR red
2) NOT TO BE red OR blue
3) NOT TO BE white
4) TO BE yellow
5) TO BE red, white OR yellow
If two balls were selected with replacement; what is the probability of
1) both the balls to be white
2) first ball to be red and second ball to be white
3) none to be yellow
4) to be red OR white Or red AND white
5) second ball NOT to be a blue
6) first ball to be a yellow
7) at least one ball to be blue
8) for the most part one to be red
9) first to be white and second NOT to be white
10) only one to be red
Answer by Boreal(15235)   (Show Source):
You can put this solution on YOUR website! 50 balls
1.20/50 or 2/5
2.White or yellow so 15/50 or 3/10
3.not to be white 40/50 or 4/5
4.to be yellow 5/50 or 1/10
5.To be red, white or yellow, 30/50 or 3/5
===
1.10/50*10/50 or 1/25
2.15/50*10/50 which is 3/50.
3.0.9^0.81
4.Red or white is 1/2 ^2=1/4; red and white is 3/10*1/5 or 3/50.
5.30/50 or 3/5
6.1/10
7.first2/5*second 2/5=4/25 for both and 2/5*3/5 plus 3/5*2/5=12/25 for 1, total is 16/25 for at least one ball to be blue.
8.not clear.
9.1/5*4/5=4/25
10.one red ball is 3/10. Only 1 is 3/10*7/10 + 7/10*3/10 or 42/100 or 0.42.
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