SOLUTION: Hi alan and bob share a sum of money. If alan gives1/4 of his share to bob, bob will have twice as much as alan. What was the ratio of alans share to bobs share at first. thank

Algebra ->  Customizable Word Problem Solvers  -> Misc -> SOLUTION: Hi alan and bob share a sum of money. If alan gives1/4 of his share to bob, bob will have twice as much as alan. What was the ratio of alans share to bobs share at first. thank      Log On

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Question 1105585: Hi
alan and bob share a sum of money. If alan gives1/4 of his share to bob, bob will have twice as much as alan. What was the ratio of alans share to bobs share at first.
thanks

Answer by ikleyn(52858) About Me  (Show Source):
You can put this solution on YOUR website!
.
Let A = amount of Alan's money (shares ?)
    B = amount of Bob's  money.


The condition says that %28B%2B0.25A%29%2F%28A+-+0.25A%29 = 2.    (1)


Simplify the ratio in the left side, step by step. You will have

%28B%2B0.25A%29%2F%28A+-+0.25A%29 = %28B%2B0.25%29%2F%280.75A%29 = B%2F%280.75%2AA%29 + %280.25%2AA%29%2F%280.75%2AA%29 = B%2F%280.75%2AA%29 + 0.25%2F0.75 = B%2F%280.75%2AA%29 + 1%2F3 = %284%2F3%29%2A%28B%2FA%29 + 1%2F3.


So we can write (1) in an equivalent form

%284%2F3%29%2A%28B%2FA%29 + 1%2F3 = 2,


which implies  

%284%2F3%29%2A%28B%2FA%29 = 2 - 1%2F3,  ====>  %284%2F3%29%2A%28B%2FA%29 = 5%2F3  ====>  B%2FA = %285%2F3%29%2A%283%2F4%29 = 5%2F4.


Answer.  The ratio of Alan' share to Bob' share at first was  A%2FB = 4%2F5.