SOLUTION: If car 1 is traveling at 60mph, and car 2 is 1/2 mile behind car 1, but traveling at 70mph, how many miles will it take car 2 to catch car 1?

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Question 1105464: If car 1 is traveling at 60mph, and car 2 is 1/2 mile behind car 1, but traveling at 70mph, how many miles will it take car 2 to catch car 1?
Answer by ikleyn(52879) About Me  (Show Source):
You can put this solution on YOUR website!
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1 - One-line solution, Physics style

    The distance under the question is %2870%2A0.5%29%2F%2870-60%29 = 35%2F10 = 3.5 miles.


2 - One-line solution, Physics style with more explanations

    The distance under the question is %2870%2A0.5%29%2F%2870-60%29 = 35%2F10 = 3.5 miles.

        Explanations.

    70-60 = 10 mph in the denominator is the relative speed of the cars, i.e. the rate of decreasing the distance between them.


    0.5%2F%2870-60%29 is the time for the second car to catch the car 1.


    Thus  %2870%2A0.5%29%2F%2870-60%29 is "how many miles will it take car 2 to catch car 1".


3 - Algebra style solution using equation

    The equation is

    70*t = 60*t + 0.5,

    which says that the distance to catch for the car 2 is 70*t miles and is 0.5 miles longer than 60*t, which is the distance to travel for the car 1.


    From the equation,

    t = 0.5%2F%2870-60%29

    is the catching time for the car 2.


    Hence,  %2870%2A0.5%29%2F%2870-60%29  is the distance to catch for the car 2, exactly as it was explained in Solutions 1 and 2.

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For the introductory lessons on Travel and Distance see the lessons
    - Travel and Distance problems
    - Travel and Distance problems for two bodies moving in opposite directions
    - Travel and Distance problems for two bodies moving in the same direction (catching up)
in this site.