SOLUTION: A painter can finish a painting job 2 hours longer than his fellow-painter. After painting for one hour, his fellow-painter joined him and they finished the job in 3 hours. How lon
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Question 1104926: A painter can finish a painting job 2 hours longer than his fellow-painter. After painting for one hour, his fellow-painter joined him and they finished the job in 3 hours. How long will it take each working alone to finish the job? Answer by jorel1380(3719) (Show Source):
You can put this solution on YOUR website! Let the first painter's time be n. Then his partner's time is n-2. So:
1/n+3/n+3/(n-2)=1
n-2+3n-6+3n=nē-2n
7n-8=nē-2n
nē-9n+8=0
(n-8)(n-1)=0
n=8 or 1
Discarding the value of 1, we get the first painter's time as 8 hours working alone, and his fellow-painter's time as 6 hours
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