Question 1104897: I am supposed to find the perimeter of square ABCD. Apparently I should have enough information to get it in normal integers, but I don't think that I have enough information. I know that the measure of angle D is (2x+40)degrees, and that side AB equals x-15. Do I have enough to go on? If so, where do I start? Thanks for helping!
Answer by Alan3354(69443)   (Show Source):
You can put this solution on YOUR website! I am supposed to find the perimeter of square ABCD. Apparently I should have enough information to get it in normal integers, but I don't think that I have enough information. I know that the measure of angle D is (2x+40)degrees, and that side AB equals x-15. Do I have enough to go on? If so, where do I start? Thanks for helping!
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All angles are equal in a square, and the sum is 360.
I know that the measure of angle D is (2x+40)degrees
---> 4*(2x+40) = 360
x = 25 degrees
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Then, all sides of a square are equal.
So, 4*(x-15) = a side = 40
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Perimeter = 4*side length
= 160
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A poorly written problem, IMO.
If the units were to be ignored, that should have been stated.
A lot of math problems are written by people who don't know what they're talking about.
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