SOLUTION: How do I write an equation in slope-intercept form of the line that passes through the given points (2,6) and (-4,-2)?

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Question 1104849: How do I write an equation in slope-intercept form of the line that passes through the given points (2,6) and (-4,-2)?

Found 2 solutions by josgarithmetic, ikleyn:
Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
%286-%28-2%29%29%2F%282-%28-4%29%29
+8%2F6
4%2F3, the slope.


y=%284%2F3%29x%2Bb
y-%284%2F3%29x=b
b=y-%284%2F3%29x
b=6-%284%2F3%292
b=6-8%2F3=18%2F3-8%2F3
b=10%2F3

highlight%28y=%284%2F3%29x%2B10%2F3%29




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(mistake removed)

Answer by ikleyn(52814) About Me  (Show Source):
You can put this solution on YOUR website!
.
How do I write an equation in slope-intercept form of the line that passes through the given points (2,6) and (-4,-2)?
~~~~~~~~~~~~~~ 

Slope = dy%2Fdx = %28%28-2%29-6%29%2F%28%28-4%29-2%29 = %28-8%29%2F%28-6%29 = 4%2F3.


The equation in the point-intercept form is

y - 6 = %284%2F3%29%2A%28x-2%29,   or, equivalently,  in the slope intercept form


y = %284%2F3%29%2Ax + 31%2F3.   <<<<----==== It is your final answer.

The solution and the answer by @josgarithmetic are   W R O N G .