SOLUTION: In 21 years kayleen will be four times older Han she is today. What is her current age.

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Question 1104835: In 21 years kayleen will be four times older Han she is today. What is her current age.

Found 4 solutions by josgarithmetic, stanbon, josmiceli, Alan3354:
Answer by josgarithmetic(39616)   (Show Source):
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Unknown age variables, k for Kayleen and h for Han

k+21=4(h+21), or depending on how wording was meant, k+21=(h+21)+4(h+21).

Some of the problem description was not included in your posted question.

Answer by stanbon(75887)   (Show Source):
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In 21 years kayleen will be four times older Han she is today. What is her current age.
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K+21 = 4K
3K = 21
K = 7 yrs
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Cheers
Stan H.
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Answer by josmiceli(19441)   (Show Source):
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Let = her current age

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Her current age is 7
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check:

OK

Answer by Alan3354(69443)   (Show Source):
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In 21 years kayleen will be four times older Han she is today. What is her current age.
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4x older = 5 times as old.
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1 time older = 100% older
2 times older = 200% older
3 times older = 300% older
4 times older = 400% older = 5 times as old.
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K = her age
K + 21 = 5K
4K = 21
K = 5.25 years of age.
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"current age" is redundant.
Ask "What is her age?" as in, "How old is she?"
No need to say "current"
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PS It's disappointing that other tutors seem to think 4 times older is the same as 4 times as old.