SOLUTION: The area of a rectangle is 42yd^2, and the length of the rectangle is 5yd more than twice the width. Find the dimensions of the rectangle.
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Question 1104420: The area of a rectangle is 42yd^2, and the length of the rectangle is 5yd more than twice the width. Find the dimensions of the rectangle. Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! The area of a rectangle is 42yd^2, and the length of the rectangle is 5yd more than twice the width. Find the dimensions of the rectangle.
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L = 2W+5
L*W = 42
