SOLUTION: Direct Variations: The amount of electric current required to melt a fuse wire varies as the three-halves power of the diameter. if the current required to melt a wire of diamet

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Question 1104356: Direct Variations:
The amount of electric current required to melt a fuse wire varies as the three-halves power of the diameter. if the current required to melt a wire of diameter 0.02 inch is 15 amperes, what current will be required to melt a wire of the same material having a diameter of 0.08 inch?

Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
The amount of electric current required to melt a fuse wire varies as the three-halves power of the diameter.
if the current required to melt a wire of diameter 0.02 inch is 15 amperes, what current will be required to melt a wire of the same material having a diameter of 0.08 inch?
:
let a = current when diameter is .08"
A direct variation equation
a%2F15 = .08%5E%283%2F2%29%2F.02%5E%283%2F2%29
cross multiply
.02%5E%283%2F2%29a = .08%5E%283%2F2%29%2A15
Calc
.002828a = .022627*15
a = .339411%2F.002828
a = 120 amps to blow a .08" fuse wire