SOLUTION: Direct Variations:
The amount of electric current required to melt a fuse wire varies as the three-halves power of the diameter. if the current required to melt a wire of diamet
Algebra ->
Percentage-and-ratio-word-problems
-> SOLUTION: Direct Variations:
The amount of electric current required to melt a fuse wire varies as the three-halves power of the diameter. if the current required to melt a wire of diamet
Log On
Question 1104356: Direct Variations:
The amount of electric current required to melt a fuse wire varies as the three-halves power of the diameter. if the current required to melt a wire of diameter 0.02 inch is 15 amperes, what current will be required to melt a wire of the same material having a diameter of 0.08 inch? Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! The amount of electric current required to melt a fuse wire varies as the three-halves power of the diameter.
if the current required to melt a wire of diameter 0.02 inch is 15 amperes, what current will be required to melt a wire of the same material having a diameter of 0.08 inch?
:
let a = current when diameter is .08"
A direct variation equation =
cross multiply a =
Calc
.002828a = .022627*15
a =
a = 120 amps to blow a .08" fuse wire