SOLUTION: A motorboat takes
5
hours to travel
150mi
going upstream. The return trip takes
3
hours going downstream. What is the rate of the boat in still water and what is the ra
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-> SOLUTION: A motorboat takes
5
hours to travel
150mi
going upstream. The return trip takes
3
hours going downstream. What is the rate of the boat in still water and what is the ra
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Question 1104348: A motorboat takes
5
hours to travel
150mi
going upstream. The return trip takes
3
hours going downstream. What is the rate of the boat in still water and what is the rate of the current? Found 2 solutions by josgarithmetic, ikleyn:Answer by josgarithmetic(39617) (Show Source):
You can put this solution on YOUR website! .
A motorboat takes 5 hours to travel 150mi going upstream. The return trip takes 3 hours going downstream.
What is the rate of the boat in still water and what is the rate of the current?
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Let x=rate of boat in still water
let c=rate of current
Then (x+c) is the rate of boat downstream
(x-c) is the rate of boat upstream
rate =
Rate upstream x-c = .
Rate downstream x+c = .
Simplify:
x - c = 30 (1)
x + c = 50 (2)
Add the equations (1) and (2). You will get
2x = 30 + 50 = 80 ====> x = = 40.
Answer. Rate of the boat in still water = 40 mph.
Rate of current = 10 mph.