SOLUTION: Mr. Gomez rode to work averaging 45 miles per hour. He averaged 55 miles per hour on the trip home from work. If he spent a total of 6 hours driving to and from work, How many mile

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Question 1104305: Mr. Gomez rode to work averaging 45 miles per hour. He averaged 55 miles per hour on the trip home from work. If he spent a total of 6 hours driving to and from work, How many miles is his work from his home

Found 3 solutions by josgarithmetic, ikleyn, greenestamps:
Answer by josgarithmetic(39616) About Me  (Show Source):
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                  SPEED      TIME       DISTANCE'
GOING              45        d/45          d
RETURN             55        d/55          d
TOTAL                         6

highlight_green%28d%2F45%2Bd%2F55=6%29

-
d%281%2F45%2B1%2F55%29=6
%28d%2F45%29%2811%2F11%29%2B%28d%2F55%29%289%2F9%29=6
%2811d%2B9d%29%2F%289%2A5%2A11%29=6
%2820%2F%289%2A5%2A11%29%29d=6
d=6%2A%289%2A5%2A11%29%2F20
d=%283%2A9%2A11%29%2F2
.


Answer by ikleyn(52775) About Me  (Show Source):
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.
Your "time" equation is


d%2F45 + d%2F55 = 6.


Multiply each term by 45*55. You will get


55d + 45d = 6*45*55  ====>  100d = 6*45*55  ====>  d = %286%2A45%2A55%29%2F100 = %283%2A9%2A11%29%2F2 = 148.5.


Answer.  148.5 miles.


Answer by greenestamps(13198) About Me  (Show Source):
You can put this solution on YOUR website!


Here is a different way of solving this kind of problem. Try it and see if you like it better than the traditional method shown by the other tutors.

(Or not....)

The distances there and back are the same; the ratio of the speeds is 55:45, or 11:9.

That means the ratio of times at the two different speeds is 9:11.

Since he spent a total of 6 hours driving, 9/20 of that time was at the higher speed and 11/20 was at the lower speed.

The number of miles traveled in 9/20 of 6 hours at 55mph is %289%2F20%29%286%29%2855%29+=+%289%2A6%2A55%29%2F20+=+%289%2A33%29%2F2+=+297%2F2+=+148.5