SOLUTION: A ball is thrown vertically upward from the top of a
building 96 feet tall with an initial velocity of 80 feet
per second. The distance, s (in feet), of the ball from
the ground
Algebra ->
Quadratic Equations and Parabolas
-> SOLUTION: A ball is thrown vertically upward from the top of a
building 96 feet tall with an initial velocity of 80 feet
per second. The distance, s (in feet), of the ball from
the ground
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Question 1103985: A ball is thrown vertically upward from the top of a
building 96 feet tall with an initial velocity of 80 feet
per second. The distance, s (in feet), of the ball from
the ground after t seconds is given by the function:
𝑠(𝑡) = 96 + 80𝑡 − 16𝑡^2
a.) How long does it take for the ball to reach its
highest point?
b.) What is the maximum height the ball reaches?
You can put this solution on YOUR website! A ball is thrown vertically upward from the top of a building 96 feet tall with an initial velocity of 80 feet per second. The distance, s (in feet), of the ball from the ground after t seconds is given by the function:
��(��) = 96 + 80�� − 16��^2
seeing this graphically is helpful
a.) How long does it take for the ball to reach its
highest point?
This is a quadratic equation, max occurs on the axis of symmetry x=-b/(2a)
t =
t = 2.5 seconds
:
b.) What is the maximum height the ball reaches?
Replace t with 2.5 to find s
s = -16(2.5^2) + 80(2.5) + 96
s = -16(6.25 )+ 200 + 96
s = -100 + 296
s = 196 ft is max height, green line
