SOLUTION: Sandra is rowing a canoe. Her rate of speed in still water is 6 miles per hour. It takes her 3 hours to travel 10 miles round trip. If she rows at a constant speed, determine the r
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-> SOLUTION: Sandra is rowing a canoe. Her rate of speed in still water is 6 miles per hour. It takes her 3 hours to travel 10 miles round trip. If she rows at a constant speed, determine the r
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Question 1103907: Sandra is rowing a canoe. Her rate of speed in still water is 6 miles per hour. It takes her 3 hours to travel 10 miles round trip. If she rows at a constant speed, determine the rate of the current?
Let v be the rate of current, in miles per hour.
Notice that one way distance is 5 miles.
Then Sandra's rate rowing downstream is (6+v) miles per hour, and the time rowing 6 miles downstream is hours.
Sandra's rate rowing upstream is (6-v) miles per hour, and the time rowing 6 miles upstream is hours.
The time equation is
+ = 3 hours.
To solve it, multiply both sides by (6+v)*(6-v). You will get
5*(6-v) + 5*(6+v) = 3*(6^2-v^2),
60 = 108 - 3v^2 ====> 3v^2 = 108 - 60 = 48 ====> v^2 = = 16 ====> v = 4 miles per hour.
Answer. The rate of the current is 4 mph.