SOLUTION: The amount of fill (weight of contents) put into a glass jar of spaghetti sauce is normally distributed with mean μ = 848 grams and standard deviation of σ = 15 grams.
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-> SOLUTION: The amount of fill (weight of contents) put into a glass jar of spaghetti sauce is normally distributed with mean μ = 848 grams and standard deviation of σ = 15 grams.
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Question 1103809: The amount of fill (weight of contents) put into a glass jar of spaghetti sauce is normally distributed with mean μ = 848 grams and standard deviation of σ = 15 grams.
(a) Describe the distribution of x, the amount of fill per jar.
skewed right
normal
skewed left
chi-square
(b) Find the probability that one jar selected at random contains between 842 and 863 grams. (Give your answer correct to four decimal places.)
(c) Describe the distribution of x, the mean weight for a sample of 27 such jars of sauce.
skewed right
normal
skewed left
chi-square
(d) Find the mean of the x distribution. (Give your answer correct to the nearest whole number.)
(ii) Find the standard error of the x distribution. (Give your answer correct to two decimal places.)
(e) Find the probability that a random sample of 27 jars has a mean weight between 842 and 863 grams. (Give your answer correct to four decimal places.)
You can put this solution on YOUR website! This is presumably normally distributed.
z=(x-mean)/sd=(842-848)/15=-6/15=-0.4
z=(863-848)/15=+1
probability of z between those two numbers is 0.4968
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The next part is normally distributed (at least no reason given to suggest it isn't).
Mean is 848
The z values have the sd modified to be s/(sqrt(27)=2.89
Therefore, the z values will be between -6/2.89=-2.08 and 15/2.89=5.19
That probability is now 0.9812.
