The complex number 3+4j, multiply by j, by j2,
and by j3.
We just need to know that j2 = -1
We start with 3+4j,
(3+4j)
multiply by j,
(3+4j)j = j(3+4j) = 3j+4j2 = 3j+4(-1) = 3j-4 = -4+3j
by j2,
(-4+3j)j2 = (-4+3j)(-1) = (-1)(-4+3j) = 4-3j
and by j3.
(4-3j)j3 = (4-3j)(j2+1) = (4-3j)(j2j1) = (4-3j)(-1)(j) = (4-3j)(-j) =
(-j)(4-3j) = -4j+3j2 = -4j+3(-1) = -4j-3 = -3-4j
Edwin
