SOLUTION: Two factory plants are making TV panels. Yesterday, Plant A produced 16,000 panels. Two percent of the panels from Plant A and 5% of the panels from Plant B were defective.

Algebra ->  Linear-equations -> SOLUTION: Two factory plants are making TV panels. Yesterday, Plant A produced 16,000 panels. Two percent of the panels from Plant A and 5% of the panels from Plant B were defective.      Log On


   

Question 1103702: Two factory plants are making TV panels. Yesterday, Plant A produced
16,000
panels. Two percent of the panels from Plant A and
5%
of the panels from Plant B were defective. How many panels did Plant B produce, if the overall percentage of defective panels from the two plants was
3%
?
Answer: Number of panels produced by plant B: ?
Answer by ikleyn(52814) About Me  (Show Source):
You can put this solution on YOUR website!
.
Plant A defective panels + Plant B defective panels = 0.03*Defective panels

0.02*16000               + 0.05*b                   = 0.03*(16000+b)    (counting defective panels)  ====>


320 + 0.05b = 0.03*16000 + 0.03*b

320 + 0.05b = 480 + 0.03*b

0.05b - 0.03b = 480 - 320 = 160

0.02b = 160  ====>  b = 160%2F0.02 = 1600%2F2 = 8000.


Answer.  Plant B produces 8000 panels.


Check.  0.02*16000 + 0.05*8000 = 720;  0.03*(16000+8000) = 720.   ! Correct !


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