Question 1103339: Find the point of the line passing through P1(3,5) and P2(-2,-4) and which is
a.) twice as far from P1 as from P2.
b.) three times as far from P2 as from P1.
Answer by Alan3354(69443)   (Show Source):
You can put this solution on YOUR website! Find the point of the line passing through P1(3,5) and P2(-2,-4) and which is
a.) twice as far from P1 as from P2.
b.) three times as far from P2 as from P1.
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Not clear what "point of the line" means.
If you mean point on the line:
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Calculate x & y separately.
P1(3,5) and P2(-2,-4)
For x:
dx = -5
2/3 of -5 = -10/3
3 - 10/3 = -1/3
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For y:
dy = -9
2/3 = -6
5 -6 = -1
--> (-1/3,-1)
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b.) three times as far from P2 as from P1.
That's 1/4 of the distance from P1.
Do it like the 1st one.
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