SOLUTION: Given that log(base a) x = p and log(base a) y = q, find the following: 1) log(base xy) a = ? and 2) log(base y) (ax^(2)y^(3)) = ? I've been staring at this for a good twenty mi

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: Given that log(base a) x = p and log(base a) y = q, find the following: 1) log(base xy) a = ? and 2) log(base y) (ax^(2)y^(3)) = ? I've been staring at this for a good twenty mi      Log On


   



Question 1103106: Given that log(base a) x = p and log(base a) y = q, find the following: 1) log(base xy) a = ? and 2) log(base y) (ax^(2)y^(3)) = ?
I've been staring at this for a good twenty minutes and I cannot for the life of me figure it out. Any help is much appreciated. Thanks!

Found 2 solutions by KMST, ikleyn:
Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
The hardest to understand (and remember) properties of logarithms are
flipping base and number: log%28Y%2CB%29%22=%221%2Flog%28B%2CY%29
and
change of base: log%28Y%2CX%29%22=%22log%28B%2CX%29%2Flog%28B%2CY%29 .
If you are going to "apply properties of logarithms" you need those two here.
You also need to know that log%28B%2CXY%29=log%28B%2CX%29%2Blog%28B%2CY%29 and that
log%28B%2CX%5En%29=n%2Alog%28B%2CX%29 .

1) If you do not want to (or cannot) memorize or remember properties, you do not need to.
It all flows logically from the meaning of logarithm.
log%28a%2Cx%29=p means that a%5Ep=x , and
log%28a%2Cy%29=q means that a%5Eq=y .
That means that a%5E%28p%2Bq%29=a%5Ep%2Aa%5Eq=xy ,
and if xy=a%5E%28p%2Bq%29 .
Then, you understand that
xy%5E%221+%2F+%28+p%2Bq+%29%22%22=%22%28a%5E%28p%2Bq%29%29%5E%281%2F%28p%2Bq%29%29%22=%22a%5E%22%28p%2Bq%29+%2F+%28p%2Bq%29%22%22=%22a%5E1=a ,
and the fact that xy%5E%221+%2F+%28+p%2Bq+%29%22=a means that
log%28xy%2Ca%29%22=%22highlight%281%2F%28p%2Bq%29%29 .

INVOKING PROPERTIES OF LOGARITHMS:
1)
log%28xy%2Ca%29%22=%221%2Flog%28a%2Cxy%29%22=%221%2F%28log%28a%2Cx%29%2Blog%28a%2Cy%29%29%22=%22highlight%281%2F%28p%2Bq%29%29 .

2)
log%28y%2Cax%5E2y%5E3%29%22=%22log%28y%2Ca%29%22%2B%22log%28y%2Cx%5E2%29%22%2B%22log%28y%2Cy%5E3%29%22=%22log%28y%2Ca%29%22%2B%222log%28y%2Cx%29%22%2B%223log%28y%2Cy%29%22=%221%2Flog%28a%2Cy%29%22%2B%222log%28a%2Cx%29%2Flog%28a%2Cy%29%22%2B%223%2A1%22=%22highlight%281%2Fq%2B2p%2Fq%2B3%29
1) If you cannot memorize or remember properties, you do not need to.
It all flows logically from the meaning of logarithm.
log%28a%2Cx%29=p means that a%5Ep=x , and
log%28a%2Cy%29=q means that a%5Eq=y .
That means that a%5E%28p%2Bq%29=a%5Ep%2Aa%5Eq=xy ,
and if xy=a%5E%28p%2Bq%29 .
Then, you understand that
xy%5E%221+%2F+%28+p%2Bq+%29%22%22=%22%28a%5E%28p%2Bq%29%29%5E%281%2F%28p%2Bq%29%29%22=%22a%5E%22%28p%2Bq%29+%2F+%28p%2Bq%29%22%22=%22a%5E1=a ,
and the fact that xy%5E%221+%2F+%28+p%2Bq+%29%22=a means that
log%28xy%2Ca%29%22=%22highlight%281%2F%28p%2Bq%29%29 .
NOTE:
The "properties of logarithms" sound like something to memorize,
and something to be anxious about,
but there is no need to be scared.
log%28a%2Cx%29=p is read as
the logarithm on basea of x is p .
The exponent on base a to get x is p sounds easier,
by just replacing the word "exponent" for the scary word "logarithm."

Answer by ikleyn(52794) About Me  (Show Source):
You can put this solution on YOUR website!
.
On logarithms and their properties, see the lessons
    - WHAT IS the logarithm
    - Properties of the logarithm
    - Change of Base Formula for logarithms
    - Solving logarithmic equations
    - Using logarithms to solve real world problems
in this site.

Also,  you have this free of charge online textbook in ALGEBRA-I in this site
    - ALGEBRA-I - YOUR ONLINE TEXTBOOK.

The referred lessons are the part of this online textbook under the topic "Logarithms".


Save the link to this online textbook together with its description

Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson

to your archive and use it when it is needed.