SOLUTION: Factorise {{{x^2-2x-3}}}

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Question 1103056: Factorise x%5E2-2x-3
Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
Solved by pluggable solver: Factoring Quadratics with a leading coefficient of 1 (a=1)
In order to factor 1%2Ax%5E2%2B-2%2Ax%2B-3, first we need to ask ourselves: What two numbers multiply to -3 and add to -2? Lets find out by listing all of the possible factors of -3


Factors:

1,3,

-1,-3,List the negative factors as well. This will allow us to find all possible combinations

These factors pair up to multiply to -3.

(-1)*(3)=-3

Now which of these pairs add to -2? Lets make a table of all of the pairs of factors we multiplied and see which two numbers add to -2

||
First Number|Second Number|Sum
1|-3|1+(-3)=-2
-1|3|(-1)+3=2
We can see from the table that 1 and -3 add to -2.So the two numbers that multiply to -3 and add to -2 are: 1 and -3 Now we substitute these numbers into a and b of the general equation of a product of linear factors which is: %28x%2Ba%29%28x%2Bb%29substitute a=1 and b=-3 So the equation becomes: (x+1)(x-3) Notice that if we foil (x+1)(x-3) we get the quadratic 1%2Ax%5E2%2B-2%2Ax%2B-3 again