SOLUTION: John can jog twice as fast as he can walk. He was able to jog the first 5 miles to his grandmother's house, but then he tired and walked the remaining 2 miles. If the total trip to

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Question 1102955: John can jog twice as fast as he can walk. He was able to jog the first 5 miles to his grandmother's house, but then he tired and walked the remaining 2 miles. If the total trip took 0.75 hours, then what was his average jogging speed?
Answer by josgarithmetic(39630) About Me  (Show Source):
You can put this solution on YOUR website!


              SPEED     TIME     DISTANCE

JOG            2r       5/(2r)     5

WALK            r       2/r        2

TOTAL                    0.75





5%2F%282r%29%2B2%2Fr=0.75



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5%2F%282r%29%2B4%2F%282r%29=0.75



9%2F%282r%29=0.75



9=%283%2F4%292r



9=%283%2F2%29r



r=%282%2F3%299



highlight%28r=6%29---------walking speed

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highlight%2812%29-----------jogging speed