.
The total space of events consists of 5*4*3 = 60 3-digit numbers, consisting of non-repeating digits 1, 2, 3, 4 and 5.
Of them, only those that start with 5 and end with 2 or 4 are even greater than 500.
If the last digit is "2", then the second digit is any of 1, 3, and 4 (3 possibilities).
If the last digit is "4", then the second digit is any of 1, 3, and 2 (3 possibilities).
In all, there are 3+3 = 6 of these "eligible" numbers.
The probability under the question is
=
.