SOLUTION: Ref. Question 1102916: Question re-worded; The wheels of a carriage take one more second to revolve, resulting in the rate per hr. being 2 2/3 miles less. Determine rate.

Algebra ->  Customizable Word Problem Solvers  -> Misc -> SOLUTION: Ref. Question 1102916: Question re-worded; The wheels of a carriage take one more second to revolve, resulting in the rate per hr. being 2 2/3 miles less. Determine rate.      Log On

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Question 1102925: Ref. Question 1102916:
Question re-worded;
The wheels of a carriage take one more second to revolve, resulting in the rate per hr. being 2 2/3 miles less. Determine rate.
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
The wheels of a carriage take one more second to revolve, resulting in the rate per hr. being 2 2/3 miles less.
Determine rate.
:
let r = original rate in mph
then using the decimal equiv of 2/3
(r - 2.6667) = the slower rate in mph
:
Assuming the revolutions in rpm:
original rev takes 60 sec,
slower rev take 61 sec
:
Using an inverse relationship, (faster speed means less time)
r%2F%28%28r-2.6667%29%29 = 61%2F60
Cross multiply
60r = 61(r-2.6667)
60r = 61r - 1622%2F3
60r - 61r = -1622%2F3
-r = -1622%2F3
r = 1622%2F3 mph is the original speed ant
1622%2F3- 22%2F3 = 160 mph is the slower speed
:
;
Not sure if I interpreted this correctly. Let me know please, ankor@att.net