SOLUTION: Find the values for c and d that would make the following equation true. (cy^3)(9y^d)=18y^6

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: Find the values for c and d that would make the following equation true. (cy^3)(9y^d)=18y^6      Log On


   

Question 1102779: Find the values for c and d that would make the following equation true.
(cy^3)(9y^d)=18y^6
Found 2 solutions by Boreal, Edwin McCravy:
Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
cy^3*9y^d=18y^6
break it apart
the constants are c*9=18 so c=2
the variables are y^3*y^d=y^6
so 3+d=6
d=3
c is 2, d is 3

Answer by Edwin McCravy(20060) About Me  (Show Source):
You can put this solution on YOUR website!
(cy^3)(9y^d) = 18y^6

Coefficient c on the left has to be 2 so that when we 
multiply it by 9 we'll get the coefficient 18 on the
right side. So we have: 

(2y^3)(9y^d) = 18y^6

Exponent d has to be 3 so that when we add the exponents 
3 and d of y on the left side, we'll get the exponent of
y on the right side, which is 6.  So we have:

(2y^3)(9y^3) = 18y^6

Edwin