SOLUTION: Ina Crespo rowed 18 miles down the Habashabee River in 2 hours, but the return trip took her 4.5 hours. Find the rate Ina rows in still river and the rate of the current. Let x rep
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-> SOLUTION: Ina Crespo rowed 18 miles down the Habashabee River in 2 hours, but the return trip took her 4.5 hours. Find the rate Ina rows in still river and the rate of the current. Let x rep
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Question 1102599: Ina Crespo rowed 18 miles down the Habashabee River in 2 hours, but the return trip took her 4.5 hours. Find the rate Ina rows in still river and the rate of the current. Let x represent the rate Ina can row in still river and let y represent the rate of the current. Found 2 solutions by josgarithmetic, ikleyn:Answer by josgarithmetic(39630) (Show Source):
You can put this solution on YOUR website! b=2, time downstream
u=4.5, time upstream
d=18, distance each way
r, unknown speed no current
c, unknown speed of current
SPEED TIME DISTANCE
DOWNSTREAM r+c b d
UPSTREAM r-c u d
You can put this solution on YOUR website! .
Ina Crespo rowed 18 miles downstream the Habashabee River in 2 hours, but the return trip took her 4.5 hours.
Find the rate Ina rows in still water and the rate of the current.
Let x represent the rate Ina can row in still water and let y represent the rate of the current.
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Let x represent the rate Ina can row in still water (in miles per hour, mph).
Let y represent the rate of the current.
The effective speed going downstream is
= = 9 mph.
The effective speed going downstream is the SUM of the Ina' speed in still water and the rate of the current.
It gives you your first equation
x + y = 9. (1)
The effective speed going upstream is
= = 4 mph.
The effective speed going upstream is the DIFFERENCE of the Ina' speed in still water and the rate of the current. It gives you your second equation
x - y = 4. (2)
Thus you have this system of two equations in 2 unknowns
x + y = 9, (1) and
x - y = 4. (2)
Add the two equations. You will get
2x = 9 + 4 = 13 ====> u = = 6.5 mph.
So, you just found the Ina' speed in still water. It is 6.5 miles per hour.
Then from the equation (1) you get y = 9 - 6.5 = 2.5 mph is the current rate.
Answer. The Ina' speed in still water is 6.5 mph.
The current rate is 2.5 mph.