SOLUTION: The measure of each interior angle of a regular polygon is 24 more than 38 times the measure of each exterior angle. Find the number of sides of the polygon. I attempted this by t

Algebra ->  Polygons -> SOLUTION: The measure of each interior angle of a regular polygon is 24 more than 38 times the measure of each exterior angle. Find the number of sides of the polygon. I attempted this by t      Log On


   



Question 1102475: The measure of each interior angle of a regular polygon is 24 more than 38 times the measure of each exterior angle. Find the number of sides of the polygon.
I attempted this by trying to solve for each interior angle.
I+24=38E and got I=178
Then, I entered that in [180(n-2)]/n =178. I got 180 and the answer should be 90. Where did I go wrong?

Found 2 solutions by Alan3354, KMST:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
The measure of each interior angle of a regular polygon is 24 more than 38 times the measure of each exterior angle. Find the number of sides of the polygon.
I attempted this by trying to solve for each interior angle.
I+24=38E and got I=178
Then, I entered that in [180(n-2)]/n =178. I got 180 and the answer should be 90. Where did I go wrong?
-------------
Int + Ext = 180
I = 38E + 24
--> 38E + 24 + E = 180
39E = 156
E = 4 degs
sides = 360/E = 90 sides

Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
If
E= measure of each exterior angle, and
I= measure of each interior angle,
then
38E= 38 times the measure of each exterior angle, and
38E%2B24= 24 more than 38 times the measure of each exterior angle.
So, your equation should have been
I=38E%2B24 .
I do not know how you got I=178 from I%2B24=38E ,
but it is often easier to work with exterior angles,
because nE=360%5Eo is much easier to remember and use
than the unwieldy nI=%28n-2%29180%5Eo .