SOLUTION: Find an equation for the ellipse with center (3, 0), foci (3, ±2) and major axis of length 6. Find an equation for the ellipse with center (3, 0), foci (3

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: Find an equation for the ellipse with center (3, 0), foci (3, ±2) and major axis of length 6. Find an equation for the ellipse with center (3, 0), foci (3      Log On


   



Question 1102379: Find an equation for the ellipse with center
(3, 0),
foci
(3, ±2)
and major axis of length 6.




Find an equation for the ellipse with center
(3, 0),
foci
(3, ±4)
and major axis of length 10.

Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
An ellipse with foci (3, ±2)
must have a center midway between the foci, at (3,0),
and its focal distance must be c=2 ,
the distance between center and either focus.
It also must have a major axis on the line x=3,
where the foci and center are located.
If the length of the major axis is 6,
the semi-major axis is a=6%2F2=3 ,
and that tells us the vertices are 3 units above and below the center,
at (3,-3) and (3,3).
In an ellipse, the semi-minor axis b is related to a and c by
b%5E2%2Bc%5E2=a%5E2 , so
b%5E2%2B2%5E2=3%5E2 ,
b%5E2%2B4=9 ,
b%5E2=9-4 ,
b%5E2=5 .
The equation for an ellipse where center, foci, and vertices differ only on the y-coordinate is
%28x-h%29%5E2%2Fb%5E2%2B%28y-k%29%5E2%2Fa%5E2=1 , where (h,k) is the center.
Substituting the values we now know for a, b%5E2 , h and k , we get
highlight%28%28x-3%29%5E2%2F5%2By%5E2%2F9=1%29 ,
and the ellipse, wit its foci looks like this

The equation for an ellipse with foci at (3, ±4) and major axis 10
can be found the same way.
c=4 , a=10%2F2=5 .
As 4%7D%7D+and+%7B%7B%7B5 are leg and hypotenuse of a 3-4-5 right triangle,
b=3 and b%5E2=9 .
The equation is highlight%28%28x-3%29%5E2%2F9%2By%5E2%2F25=1%29 .