SOLUTION: Steve is making a rectangular picture frame. He wants the perimeter of the frame to be no more than 96 inches. He also wants the length of the frame to be greater than or equal to

Algebra ->  Customizable Word Problem Solvers  -> Misc -> SOLUTION: Steve is making a rectangular picture frame. He wants the perimeter of the frame to be no more than 96 inches. He also wants the length of the frame to be greater than or equal to       Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


   



Question 1102344: Steve is making a rectangular picture frame. He wants the perimeter of the frame to be no more than 96 inches. He also wants the length of the frame to be greater than or equal to the square of 4 inches less than its width.
Create a system of inequalities to model the above situation and use it to determine how many of the solutions are viable.
a.) Part of the solution region includes a negative length; therefore, all solutions are not viable for the given situation.
b.) The entire solution region is viable.
c.)No part of the solution region is viable because the length or width cannot be negative.
d.) Part of the solution region includes a negative width; therefore, not all solutions are viable for the given situation.

Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
p, perimeter
w, width
L, length
system%28w%2BL%3C=48%2CL%3E=%28w-4%29%5E2%29
Also
system%28w%3E0%2CL%3E0%29


(attempt at a )graph may help:
graph%28400%2C400%2C-2%2C50%2C-2%2C50%2Cy=-x%2B48%2Cy=%28x-4%29%5E2%29
Acceptable region is above the parabola, to the right of the y-axis and below the line. y-axis is for length and x-axis is for width.