SOLUTION: Ref. Question 1102280: Ikleyn; I confirm your editing of my problem and agree with it. Thanks.

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Question 1102314: Ref. Question 1102280:
Ikleyn;
I confirm your editing of my problem and agree with it. Thanks.

Answer by ikleyn(52898) About Me  (Show Source):
You can put this solution on YOUR website!
.
I just solved and answered this problem at the link
https://www.algebra.com/algebra/homework/word/misc/Miscellaneous_Word_Problems.faq.question.1102280.html

https://www.algebra.com/algebra/homework/word/misc/Miscellaneous_Word_Problems.faq.question.1102280.html

For your convenience, I copy and paste this solution here again:
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Below is your input with my editing:

Specific gravity of gold: highlight%28cross%2819259%29%29 19.259.


Specific gravity of quartz: highlight%28cross%282652%29%29 2.652.


Determine ounces of gold in an mass of 210 oz. of both, the specific gravity is highlight%28cross%284562%29%29 4.562.


Specific gravity is the weight of a volume of a substance divided by the weight of the same highlight%28cross%28amount%29%29 volume of water. 

Water weighs 62.5 lbs. per cu. ft.     <<<---=== In my solution I do not need this info.
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First step is to find the fraction "x" of the gold in 210 oz. of mixture of the specific gravity 4.562.


For it, use the density equation

    x*19.259 + (1-x)*2.652 = 4.562.


    19.259x + 2.652 - 2.652x = 4.562  ====>  16.607x = 4.562 - 2.652 = 1.91  ====>  x = 1.91%2F16.607 = 0.115.


So, the mass fraction of the gold in the mixture is 0.115.



Next step determine the mass of the gold in the mass of 210 oz of the mixture:

    gold mass = 0.115*210 = 24.15 oz.

Answer. The mass of the gold is 24.15 oz.


Solved.