SOLUTION: Twice the the smallest of three consecutive ODD integers is seven more than the largest. Find the integers. Let the first one be X.

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Question 110231: Twice the the smallest of three consecutive ODD integers is seven more than the largest. Find the integers. Let the first one be X.
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
If they are odd, I like to call the smallest 2x+%2B+1
That way, it can only be odd. then,
2x+%2B+1, 2x+%2B+3, 2x+%2B+5 are the 3 integers
2%282x+%2B+1%29+=+%282x+%2B+5%29+%2B+7
4x+%2B+2+=+2x+%2B+12
2x+=+10
2x+%2B+1+=+11
11, 13, 15 are the integers
check
2%2A11+=+15+%2B+7
22+=+22
OK